Question

resolva a questão ( L )
por favor
equação biquadrática

Answer 1

$\frac{3x^2+x}{x+1}+\frac{3x^2}{x-1}=\frac{x(13x-1)}{x^2-1}\\\\ \frac{(3x^2+x)(x-1)+(3x^2)(x+1)=x(13x-1)}{x^2-1}\\\\ (3x^2+x)(x-1)+(3x^2)(x+1)=x(13x-1)\\\\ (3x^3-3x^2+x^2-x)+(3x^3+3x^2)=13x^2 -x\\\\ 6x^3+x^2=13x^2\\\\ 6x^3-12x^2=0\\\\ 6x^2(x-2)=0\\\\ 6x^2=0 \implies x=0\\\\ x-2=0 \implies x=2$