• Matéria: Matemática
  • Autor: RadiolarioVerde
  • Perguntado 9 anos atrás

Como descobrir o valor de y? Y= [(3^121)+(3^120)-(3^119)]/[(3^120)+2.(3^119)]

Respostas

respondido por: FdASO
0
Y= [(3^{121})+(3^{120})-(3^{119})]/[(3^{120})+2.(3^{119})]\\\\
Y= \frac{(3^{121})+(3^{120})-(3^{119})}{(3^{120})+2.(3^{119})}\\\\
Y= \frac{(3^2.3^{119})+(3.3^{119})-(3^{119})}{(3.3^{119})+2.(3^{119})}\\\\
Y= \frac{9.3^{119}+3.3^{119}-3^{119}}{3.3^{119}+2.3^{119}}\\\\
Y= \frac{11.3^{119}}{5.3^{119}}\\\\
Y=\frac{11}{5}
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