Question

x ao quadrado -16x -28=0​

Answer 1

Resposta:

$S=$ {$8-4\sqrt{23}, 8+4\sqrt{23}$}

Explicação passo-a-passo:

$x^2-16x-28 = 0$

Δ $= 16^2+4.28$

Δ $= 256 +112$

Δ $= 368$

$x_1 = \frac{16-4\sqrt{23}}{2}\\x_1 = 8-2\sqrt{23}$

$x_2= \frac{16+4\sqrt{23}}{2}\\x_2=8+2\sqrt{23}$

$S=$ {$8-4\sqrt{23}, 8+4\sqrt{23}$}