Question

ajuda.!!! log4 (2x+6) =3​

Answer 1

Olá!

$log4\:\left(2x+6\right)\:=3​\\\\\log _{10}\left(4\right)\left(2x+6\right)=3\\\\\frac{2\log _{10}\left(2\right)\left(2x+6\right)}{2\log _{10}\left(2\right)}=\frac{3}{2\log _{10}\left(2\right)}\\\\2x+6=\frac{3}{2\log _{10}\left(2\right)}\\\\2x+6-6=\frac{3}{2\log _{10}\left(2\right)}-6\\\\2x=\frac{3}{2\log _{10}\left(2\right)}-6\\\\\frac{2x}{2}=\frac{\frac{3}{2\log _{10}\left(2\right)}}{2}-\frac{6}{2}\\\\x=\frac{3-12\log _{10}\left(2\right)}{4\log _{10}\left(2\right)}\\\\Decimal: x=-0,50855...$

Espero ter ajudado, bons estudos!