Question

8)Utilizando o processo algébrico de Bhaskara, determine as raízes das equação 4x²-18x+8=0.

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Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\mathsf{4x^2 -18x + 8 = 0}\rightarrow\begin{cases}\mathsf{a = 4}\\\mathsf{b = -18}\\\mathsf{c = 8}\end{cases}$

$\mathsf{\Delta = b^2 - 4.a.c}$

$\mathsf{\Delta = (-18)^2 - 4.4.8}$

$\mathsf{\Delta = 324 - 128}$

$\mathsf{\Delta = 196}$

$\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{18 \pm \sqrt{196}}{8} \rightarrow \begin{cases}\mathsf{x' = \dfrac{18 + 14}{2} = \dfrac{32}{8} = 4}\\\\\mathsf{x'' = \dfrac{18 - 14}{8} = \dfrac{4}{8} = \dfrac{1}{2}}\end{cases}}$

$\boxed{\boxed{\mathsf{S = \{4\:;\dfrac{1}{2}\}}}}$