Question

a) (+5)3=
b) (-5)3=
c) (+10)2=
d) 03=
e) (+2)5=
f) (-2)5=
g) 09=
h) (_2)4=
i) (-8)0=
Determinar o valor das potencias com numeros negativos na base.​

Answer 1

Resposta:

$a) {( + 5)}^{3} = 5 \times 5 \times 5 = 25 \times 5 = 125 \\ b) {( - 5)}^{3} = ( - 5) \times ( - 5) \times ( - 5) = 25 \times ( - 5) = - 125 \\ c) {(10)}^{2} = 10 \times 10 = 100 \\ d) {0}^{3} = 0 \times 0 \times 0 = 0$

$e) {( + 2)}^{5} = 2 \times 2 \times 2 \times 2 \times 2 = 4 \times 4 \times 2 = 16 \times 2 = 32 \\ f) {( - 2)}^{5} = ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) = 4 \times 4 \times ( - 2) = 16 \times ( - 2) = - 32 \\ g) {0}^{9} = 0 \times 0 \times 0 \times 0 \times 0 \times 0 \times 0 \times 0 \times 0 = 0$

$h) { ( - 2)}^{4} = ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) = 4 \times 4 = 16 \\ i) {( - 8)}^{0} = 1$

Answer 2

Resposta:

a) +5³= 5 x 5 x 5 = 125

b) -5³= -5 x -5 = +25 x -5 = -125

c) +10²= 10 x 10 = 100

d) 0³= 0 x 0 x 0 = 0

e) 2⁵= 2 x 2 x 2 x 2 x 2 = 32

f) -2⁵= -2 x -2 = 4 x -2 = -8 x -2 = 16 x -2 = -32

g) 0⁹= 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 x 0 = 0

h) -2⁴= -2 x -2 = 4 x -2 = -8 x -2 = 16

i) -8⁰= 1

se tiver parenteses

-8⁰= -1