Question

Calcule:

e) (-5/9)¹ =

f) (+7/8)¹ =

g) (-1/2)⁵ =

h) (-4/3)² =

Answer 1

$e) (-\frac{5}{9} )^1=-\frac{5}{9} \\ \\ f)(+\frac{7}{8} )^1= \frac{7}{8} \\ \\ g) (-\frac{1}{2} )^5=- \frac{1^5}{2^5} =- \frac{1}{32} \\ \\ h)(-\frac{4}{3} )^2= \frac{16}{9}$