Question

determine as geratriz das seguintes dízimas periódicas :a)0,3232... b)0,7878...c) 1,2444...d)0,321...e)2,345959...f)1,31222...

Answer 1

a) 0,3232... = 32/99
b) 0,7878... = 78/99
c) 1,2444... = (124-12)/90 = 112/90 = 112:2/90:2 = 56/45
d) 0,321... = (321-32)/900 = 289/900
e) 2,345959... = (23459-234)/9900 = 23225/9900 = 23225:5/9900:5 = 
4645/1980 = 4645:5/1980:5 = 929/396
f) 1,31222... = (1312-131)/900 = 1181/900