• Matéria: Matemática
  • Autor: darlysantos131191
  • Perguntado 4 anos atrás

1:resolva as expressões numemericas abaixo:
A ()3/4×14/6+3/2)÷(3/8+7/4)=
B)(3/2+1/4-3/8)÷11/2=
C)13/4÷(7/4-5/6+31/12)=
D)9/8÷(7/5+7/10-3/4)=
E)(7/4+5/2)÷25/8-9/4)=

Respostas

respondido por: raphaelramos296
1

Resposta:

A) (3/4 . 14/6 + 3/2) : (3/8 + 7/4) =

(48/24 + 3/2) : (3/8 + 7/4) =

48/24 + 3/2 = 96/48 + 72/48 = 168/48=

168/48 : (3/8 + 7/4) =

168/48 + (6/16 + 28/16) =

168/48 + 36/16 =

504/48 + 108/48 =

612/48 =

51/4

B) (3/2 + 1/4 - 3/8) : 11/2 =

(12/8 + 2/8 - 3/8) : 11/2 =

11/8 : 11/2 =

11/8 . 2/11 =

22/88 =

1/4

C) 13/4 : (7/4 - 5/6 + 31/12) =

13/4 : (21/12 - 10/12 + 31/12) =

13/4 : 41/12 =

13/4 . 12/41 =

156/164 =

39/41

D) 9/8 : (7/5 + 7/10 - 3/4) =

9/8 : (28/20 + 14/20 - 15/20) =

9/8 : 27/20

9/8 . 20/27

180/216 =

5/6

E) (7/4 + 5/2) : 25/8 - 9/4) =

(7/4 + 10/4) : 25/8 - 9/4) =

(17/4 : 25/8 - 9/4) =

(17/4 . 8/25 - 9/4) =

136/100 - 9/4 =

544/400 - 900/400 =

-356/400 =

-89/100


darlysantos131191: obgd por ter me ajudado
raphaelramos296: dnd
inhudesbandida: Raphaelramos296 me ajuda em artes
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