1:resolva as expressões numemericas abaixo:
A ()3/4×14/6+3/2)÷(3/8+7/4)=
B)(3/2+1/4-3/8)÷11/2=
C)13/4÷(7/4-5/6+31/12)=
D)9/8÷(7/5+7/10-3/4)=
E)(7/4+5/2)÷25/8-9/4)=
Respostas
respondido por:
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Resposta:
A) (3/4 . 14/6 + 3/2) : (3/8 + 7/4) =
(48/24 + 3/2) : (3/8 + 7/4) =
48/24 + 3/2 = 96/48 + 72/48 = 168/48=
168/48 : (3/8 + 7/4) =
168/48 + (6/16 + 28/16) =
168/48 + 36/16 =
504/48 + 108/48 =
612/48 =
51/4
B) (3/2 + 1/4 - 3/8) : 11/2 =
(12/8 + 2/8 - 3/8) : 11/2 =
11/8 : 11/2 =
11/8 . 2/11 =
22/88 =
1/4
C) 13/4 : (7/4 - 5/6 + 31/12) =
13/4 : (21/12 - 10/12 + 31/12) =
13/4 : 41/12 =
13/4 . 12/41 =
156/164 =
39/41
D) 9/8 : (7/5 + 7/10 - 3/4) =
9/8 : (28/20 + 14/20 - 15/20) =
9/8 : 27/20
9/8 . 20/27
180/216 =
5/6
E) (7/4 + 5/2) : 25/8 - 9/4) =
(7/4 + 10/4) : 25/8 - 9/4) =
(17/4 : 25/8 - 9/4) =
(17/4 . 8/25 - 9/4) =
136/100 - 9/4 =
544/400 - 900/400 =
-356/400 =
-89/100
darlysantos131191:
obgd por ter me ajudado
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