Question

integral indefinida de √x dx

Answer 1

$\int\limits { \sqrt{x} } \, dx = \int\limits {x^{ \frac{1}{2} }} \, dx \\\\ \frac{x^{ \frac{1}{2} + 1 }}{ \frac{1}{2} + 1 } = \frac{x^{ \frac{3}{2} }}{\frac{3}{2}} \\\\ \frac{2}{3} x^{ \frac{3}{2} } + {C}$