Question

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Answer 1

$\displaystyle \text{f(t)}=(2)^{\displaystyle(\frac{ \text t+1}{2})}$

$\displaystyle\text{Para valor de t a fun{\c c}{\~a}o ser{\'a} igual a 4096 ?} \\\\ 4096 =(2)^{\displaystyle \frac{\text t+1}{2}}\\\\ 2^{12}=2^{\displaystyle (\frac{\text t+1}{2})} \\\\ 12 = \frac{\text t+1}{2} \\\\\\ \text t+1=24 \\\\ \huge\boxed{{\text t = 23\ \text s}}\checkmark$

Letra C