• Matéria: Matemática
  • Autor: Bismark
  • Perguntado 9 anos atrás

Me ajudem, preciso resolver essa questão...

Anexos:

Respostas

respondido por: Anônimo
0

a) \text{ab}+\text{ac}=\text{a}\cdot(\text{b}+\text{c})

 

b) \text{x}^4+\text{x}^3+\text{x}^2=\text{x}^2\cdot(\text{x}^2+\text{x}+1)

 

c) \text{am}+\text{na}+\text{bm}+\text{bn}=\text{a}\cdot(\text{m}+\text{n})+\text{b}\cdot(\text{m}+\text{n})

 

=(\text{a}+\text{b})\cdot(\text{m}+\text{n})

 

d) \text{xy}-\text{yz}+\text{wx}-\text{wz}=\text{y}\cdot(\text{x}-\text{z})+\text{w}\cdot(\text{x}-\text{z})

 

=(\text{y}+\text{w})\cdot(\text{x}-\text{z})

 

e) \text{x}^2-\text{y}^2=(\text{x}+\text{y})\cdot(\text{x}-\text{y})

 

f) \text{a}^2-36=(\text{a}+6)\cdot(\text{a}-6)

 

g) \text{x}^2-14\text{x}+49=(\text{x}-7)^2

 

h) \text{y}^2+2\text{y}+1=(\text{y}+1)^2

 

i) \text{a}^2-20\text{a}+100=(\text{a}-10)^2

 

j) 9\text{x}^2+36\text{xy}+36\text{y}^2=(3\text{x}+6\text{y})^2

 

k) \text{y}^2-16\text{y}+64=(\text{y}-8)^2

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