Question

2)Dados log 2 = 0,3010; log 3 =0,4771 e log 11 = 1,0414; calcule:
a)log 22 =
b) log 33 =

Answer 1

Resposta:

a) $log 22=log(2.11)= (log 2)+(log11)=(0,3010)+(1,0414)=1,3424$

b) $log 33=log(3.11)= (log 3)+(log11)=(0,4771)+(1,0414)=1,5185$