Question

Como resolver;
2^-1 + 6 . (2/3)^-2 - (1/3)^-1

Meu resultado deu 11

Obrigada

Answer 1

Olá,

(2)^-1 = (1/2)^1 = 1/2 = 0,5
6·(2/3)^-2 = 6·(3/2)^2 = 6·(9/4) = 3·(9/2) = 27/2 = 13,5
(1/3)^-1 = (3/1)^1 = 3

0,5 + 13,5 - 3
14 - 3
11

Resposta:

11

Answer 2

2^-1 + 6• (2/3)^-2 - (1/3)^-1 =
1/2 + 6• (3/2)² - 3 =
1/2 + 6•(9/4) - 3 =
1/2 + 54/4 - 3 =
2/4 + 54/4 - 12/4 =
44/4 =

11