Question

resolva as seguintes equações:

a) x2 + 1= 10 b) x2 – 1 = 48

c) x2 – 9 = 0 d) x2 – 36= 64​

Answer 1

Olá!

a) x2 + 1= 10

$x\cdot \:2+1=10\\\\x\cdot \:2+1-1=10-1\\\\x\cdot \:2=9\\\\\frac{x\cdot \:2}{2}=\frac{9}{2}\\\\x=\frac{9}{2}$

b) x2 – 1 = 48

$x\cdot \:2-1=48\\\\x\cdot \:2-1+1=48+1\\\\x\cdot \:2=49\\\\\frac{x\cdot \:2}{2}=\frac{49}{2}\\\\x=\frac{49}{2}$

c)  x2 – 9 = 0

$x\cdot \:2-9=0\\\\x\cdot \:2-9+9=0+9\\\\x\cdot \:2=9\\\\\frac{x\cdot \:2}{2}=\frac{9}{2}\\\\x=\frac{9}{2}$

d) x2 - 36= 64

$x\cdot \:2-36=64\\\\x\cdot \:2-36+36=64+36\\\\x\cdot \:2=100\\\\\frac{x\cdot \:2}{2}=\frac{100}{2}\\\\x=50$

Espero ter ajudado, tenha boas aulas!