Question

se alguém souber agradeço.......calcule

Answer 1

$\frac{-2- \sqrt{2^2-4*1*(-3)} }{2*1} =$

$\frac{-2- \sqrt{4+12} }{2} = \frac{-2- \sqrt{16} }{2}= \frac{-2-4}{2}=-3$

$\frac{-(-7)+ \sqrt{1} }{2*6} = \frac{+7+1}{12}= \frac{8}{12} = \frac{4}{6} = \frac{2}{3}$

$\frac{-4+ \sqrt{100} }{3} = \frac{-4+10}{3} = \frac{6}{3} =2$

Answer 2

segue em anexos as respostas