Question

Considerando-se log10 2 = 0,30 e log10 3 = 0,47 , determine log10 6
(a) 1,23
(b) 0,75
(c) 0,77
(d) 1,57
(e) 0,17

Answer 1

$\boxed{\begin{array}{l}\underline{\rm Logaritmo~do~produto}\\\sf \ell og_c(a\cdot b)=\ell og_ca+\ell og_cb\end{array}}$

$\large\boxed{\begin{array}{l}\rm Considerando-se~\ell og_{10}2=0,30~e~\ell og_{10}3=0,47\\\rm determine~\ell og_{10}6\\\rm a)~1,23\\\rm b)~0,75\\\rm c)~0,77\\\rm d)~1,57\\\rm e)~0,17\end{array}}$

$\boxed{\begin{array}{l}\underline{\rm soluc_{\!\!,}\tilde ao:}\\\sf\ell og_{10}6=\ell og_{10}(2\cdot3)\\\sf\ell og_{10}6=\ell og_{10}2+\ell og_{10}3\\\sf\ell og_{10}6=0,30+0,47=0,77\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~c}}}}\end{array}}$