Question

calcule as potencias abaixo​

Answer 1

Resposta:

a) $6^{2}$ = 6 x 6 = 36

b) $(-6)^{2}$ = (-6) x (-6) = +36

c) $-6^{2}$ = - 6 x 6= -36

d) $(-2)^{3}$ = (-2) x (-2) x (-2) = -8

e) $-2^{3}$ = - 2 x 2 x 2= -8

f) $5^{0}$ = 1

g) $(-8)^{0}$ = 1

h) $(\frac{3}{2}) ^{4} = \frac{3 . 3. 3.3}{2.2.2.2} = \frac{81}{16} = 10\frac{1}{8}$

i) $(-\frac{3}{2}) ^{4} = (-\frac{3}{2}) . (-\frac{3}{2}) .(-\frac{3}{2}) .(-\frac{3}{2}) = \frac{81}{16} = 10\frac{1}{8}$

j) $(-\frac{3}{2}) ^{3} = (-\frac{3}{2}) .(-\frac{3}{2}) .(-\frac{3}{2})= -\frac{27}{8} = -3\frac{3}{8}$

k) $0^{28}$ = 0

l) $1^{32}$ = 1

m) $(-1)^{20}$= 1

n) $(-1)^{17}$= -1

o) $(-\frac{3}{5}) ^{2} = (-\frac{3}{5}) . (-\frac{3}{5}) = \frac{9}{25}$