Question

Pergunta na imagem, me ajudem por favor.

Answer 1

   $\frac{x}{y}+ \frac{y}{x} =5 ----mmc=xy$

   $\frac{x^2+y^2}{xy} = \frac{5}{xy} --\ \textgreater \ \frac{x.x+y.y}{xy} = \frac{5}{xy} --\ \textgreater \ x+y=5$

   $K^{ \frac{(x-y)^2}{xy} }$

   $\frac{(x-y)^2}{xy}= \frac{x^2-2xy+y^2}{xy} = \frac{(x^2+y^2)-2xy}{xy} =$

  =$\frac{x.x+y.y}{xy} -2= \frac{5xy}{xy}-2= 5 -2 = 3$

 Logo: Opção b --->$K^{3}$