Question

Exercício de matemática... Ajuda!

FOTO.... por favor colocar o calculo de como foi feito o exercício.
Obrigada!

Answer 1

raiz (3/4 -1/12) + raiz (1/6) - 3/2.raiz (1-1/3) =

raiz (9-1/12) + raiz (1/6) - 3/2.raiz (2/3) =

raiz (8/12) + 1/raiz (6) - raiz (18/12) =

raiz (4/6) + 1/raiz (6) - raiz (6/4) =

2/raiz (6) + 1/raiz (6) - raiz (6)/2 =

2raiz(6)/6 + raiz(6)/6 - raiz(6)/2 =

raiz(6)/3 + raiz(6)/6 - raiz(6)/2 =

(2raiz(6) + raiz(6) - raiz(6)) / 6 =

0/6 = 0

Answer 2

$\sqrt{\frac{3}{4}-x}+\sqrt{2x}-\frac{3}{2}\cdot\sqrt{1-4x}\\ \\ \sqrt{\frac{3}{4}-\frac{1}{12}}+\sqrt{2\cdot \frac{1}{12}}-\frac{3}{2}\cdot\sqrt{1-4\cdot \frac{1}{12}}=\\ \\ \sqrt{\frac{3\cdot 3-1}{12}}+\sqrt{\frac{1}{6}}-\frac{3}{2}\cdot\sqrt{1-\frac{1}{3}}=\\ \\ \sqrt{\frac{8}{12}}+\frac{1}{\sqrt{6}}-\frac{3}{2}\cdot\sqrt{\frac{3-1}{3}}=\\ \\ \sqrt{\frac{2}{3}}+\frac{1\cdot \sqrt{6}}{\sqrt{6}\cdot \sqrt{6}}-\frac{3}{2}\cdot\sqrt{\frac{2}{3}}=$

$\sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-(\frac{2}{3})^{-1}\cdot (\frac{2}{3})^{\frac{1}{2}=$

$\sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-(\frac{2}{3})^{-1+\frac{1}{2}}=\\ \\ \sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-(\frac{2}{3})^{\frac{-2+1}{2}}=\\ \\ \sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-(\frac{2}{3})^{-\frac{1}{2}}=\\ \\ \sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-(\frac{3}{2})^{\frac{1}{2}}=\\ \\ \sqrt{\frac{2}{3}}+\frac{\sqrt{6}}{6}-\sqrt{\frac{3}{2}}=$

$\frac{6\cdot \sqrt{\frac{2}{3}}+\sqrt{6}-6\cdot \sqrt{\frac{3}{2}}}{6}=\\ \\ \frac{\sqrt{36\cdot \frac{2}{3}}+\sqrt{6}- \sqrt{36\cdot \frac{3}{2}}}{6}=\\ \\ \frac{\sqrt{12\cdot 2}+\sqrt{6}- \sqrt{18\cdot 3}}{6}=\\ \\ \frac{\sqrt{24}+\sqrt{6}- \sqrt{54}}{6}=$

$\frac{2\sqrt{6}+\sqrt{6}- 3\sqrt{6}}{6}=\\ \\ \frac{0}{6}=0$