Respostas
respondido por:
14
A = 1/(\/2+\/3)
B = 1/(\/3-\/2)
A+B = 1/(\/2+\/3) + 1/(\/3-\/2)
mmc (\/2+\/3) e (\/3-\/2) = (\/2+\/3).(\/3-\/2) = \/6-\/4+\/9-\/6 = -2+3 = 1
(\/3-\/2)+(\/2+\/3) / (\/3-\/2).(\/2+\/3) =
(\/3-\/2+\/2+\/3) / (\/6+\/9-\/4-\/6) =
2\/3 / (\/9-\/4) =
2\/3 / (3-2) =
2\/3 / 1 = 2\/3
B = 1/(\/3-\/2)
A+B = 1/(\/2+\/3) + 1/(\/3-\/2)
mmc (\/2+\/3) e (\/3-\/2) = (\/2+\/3).(\/3-\/2) = \/6-\/4+\/9-\/6 = -2+3 = 1
(\/3-\/2)+(\/2+\/3) / (\/3-\/2).(\/2+\/3) =
(\/3-\/2+\/2+\/3) / (\/6+\/9-\/4-\/6) =
2\/3 / (\/9-\/4) =
2\/3 / (3-2) =
2\/3 / 1 = 2\/3
Mkse:
perfeito
respondido por:
2
Seja A= 1 / V2 + V3 e B= 1 / V3 - V2, então A+B é igual a:
A + B = 2V3
A + B = 2V3
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