Respostas
Resposta:
Explicação passo a passo:
=
−
±
2
−
4
√
2
m=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
m=2a−b±b2−4ac
Na forma padrão, identifique "a", "b" e "c" da equação original e adicione esses valores à função do segundo grau.
5
2
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1
3
+
6
=
0
5m^{2}-13m+6=0
5m2−13m+6=0
=
5
a={\color{#c92786}{5}}
a=5
=
−
1
3
b={\color{#e8710a}{-13}}
b=−13
=
6
c={\color{#129eaf}{6}}
c=6
=
−
(
−
1
3
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±
(
−
1
3
)
2
−
4
⋅
5
⋅
6
√
2
⋅
5
m=\frac{-({\color{#e8710a}{-13}}) \pm \sqrt{({\color{#e8710a}{-13}})^{2}-4 \cdot {\color{#c92786}{5}} \cdot {\color{#129eaf}{6}}}}{2 \cdot {\color{#c92786}{5}}}
m=2⋅5−(−13)±(−13)2−4⋅5⋅6
2
Explicação passo-a-passo:
b^2- 4ac
13^2-4.5.6
delta = 49. m = 13+7
-----' m = 20
2a. --'-- m = 10
2
m= 6
--- m = 3/5. s [ 3/5, 10]
10