Question

logaritmo,dados os valores log2=0,3010,log3=0,4771,log5=0,6990 e log7=0,8451 determine o valor de :log15 ,de log49,  de log108,e log5 com raiz de 7.

Answer 1

log 15 = log (3x5) = log 3 + log 5 = 0,3010 + 0,4771 = 0,7781
log 49 = log 7² = 2 . log 7 = 2 . 0,8451 = 1,6902
log 108 = log (27.4) = log (3³.2²) = log 3³ + log 2² = 3 log 3 + 2 log 2 = 3.0,4771 + 2.0,3010 = 1,4313 + 0,602 = 2,0333