Question

Sejam:
A = x2 - 2x + 1
B = x2 - 1
C = (x – 1) (2x + 3)

O MDC de A, B e C vale

Answer 1

A = x² – 2x + 1  = (x - 1)² = (x - 1)(x - 1)

B = x² – 1  = (x + 1)(x - 1)

C = x² – x = x(x - 1)

a) MDC (A,B e C) = x - 1

b)MMC (A , B e C)

(x - 1)² , (x + 1)(x - 1) , x(x - 1) | (x - 1)         >>> MDC

(x - 1)  ,     (x + 1)    ,     x       | (x - 1)

  1     ,     (x + 1)    ,     x       |  x

  1     ,     (x + 1)    ,     1       | (x + 1)

  1     ,         1        ,     1      

MMC(A , B e C) = x.(x + 1).(x - 1)²