Question

encontre o valor de x no triângulo a seguir.​

Answer 1

$\Large\boxed{\begin{array}{l}\sf cos(30^\circ)=\dfrac{x}{12}\\\sf\dfrac{\sqrt{3}}{2}=\dfrac{x}{12}\\\sf 2x=12\sqrt{3}\\\sf x=\dfrac{12\sqrt{3}}{2}\\\sf x=6\sqrt{3}\end{array}}$