Question

ALGUÉM ME AJUDA PFV
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Answer 1

Explicação passo a passo:

$b)144^{\frac{1}{2} }=\sqrt{144} =12\\c)16^{\frac{3}{4} }=\sqrt[4]{16^{3} }= 8\\f)(\frac{5}{6}) ^{\frac{5}{6} } =\sqrt[6]{ (\frac{5}{6})^{5} } \\g)0,15^{\frac{7}{2} } =\sqrt{0,15^{7} } \\h)2^{\frac{3}{5} }=\sqrt[5]{2^3} }\\ i)(2^{4})^{\frac{3}{5} } =\sqrt[5]{2^{12} } \\J)a^{\frac{6}{11} } =\sqrt[11]{a^{6} }$