Question

me ajudem pfvr, é pra hoje
d) 3y + 5 < 2
e) 7z < - 7
f) 5x - 5 + x > 2x +8 +1

Answer 1

Resposta:

D)

$3y < 2 - 5 \\ 3y < - 3 \\ y < \frac{ - 3 }{3} \\ y < - 1$

E)

$7z < - 7 \\ z < \frac{ - 7}{7} \\ z < - 1$

F)

$5x - 5 + x > 2x + 8 + 1 \\ 6x - 5 > 2x + 8 + 1 \\ 6x - 5 > 2x + 9 \\ 6x - 5 - 2x > 9 \\ 4x - 5 > 9 \\ 4x > 9 + 5 \\ 4x > 14 \\ x > \frac{14}{4} \\ x > \frac{7}{2}$