Question

$4^{x}$ = $\sqrt[3]{32}$ como resolver???

Answer 1

$4^{x} = \sqrt[3]{32}$

$( 2^{2} )^{x} = \sqrt[3]{ 2^{5} }$

$2^{2x} = 2^{ \frac{5}{3} }$ ⇒ $2x= \frac{5}{3}$ ⇒ $x= \frac{5}{6}$