Question

determine as coordenadas do ponto M (Xm, Ym) que é o ponto médio do segmento AB a) A=(3,5) e B(8,5) b) A=(5,-1) e B(1,7) c) A=(2,-1) e B (-4,-1)​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{M = \{\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{3 + 8}{2};\dfrac{5 + 5}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{11}{2};\dfrac{10}{2}\}}$

$\boxed{\boxed{\mathsf{M_{AB} = \{\dfrac{11}{2};5\}}}}\leftarrow\textsf{letra A}$

$\mathsf{M = \{\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{5 + 1}{2};\dfrac{-1 + 7}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{6}{2};\dfrac{6}{2}\}}$

$\boxed{\boxed{\mathsf{M_{AB} = \{3;3\}}}}\leftarrow\textsf{letra B}$

$\mathsf{M = \{\dfrac{x_A + x_B}{2};\dfrac{y_A + y_B}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{2 - 4}{2};\dfrac{-1 - 1}{2}\}}$

$\mathsf{M_{AB} = \{\dfrac{-2}{2};\dfrac{-2}{2}\}}$

$\boxed{\boxed{\mathsf{M_{AB} = \{-1;-1\}}}}\leftarrow\textsf{letra C}$