• Matéria: Matemática
  • Autor: krisnanmaciel8
  • Perguntado 4 anos atrás

c) 24aw + 6x2 – 12a²w3 – 6x 20x

Respondem rápido pfvvvvvvvv

Respostas

respondido por: vitoriaso601
1

Resposta:

Δ = 1² – 4.2.(– 3)

Δ = 1 + 24

Δ = 25

x = – 1 ± √25

2.2

x = – 1 ± 5

4

x' = – 1 + 5 = 4 = 1

4 4

x'' = – 1 – 5 = – 6 = – 3

4 4 2

As raízes da equação 2x² + x – 3 = 0 são 1 e – 3/2.

Δ = 6² – 4.(– 1).(– 5)

Δ = 36 – 20

Δ = 16

x = – 6 ± √16

2.(– 1)

x = – 6 ± 4

– 2

x' = – 6 + 4 = – 2 = 1

– 2 – 2

x'' = – 6 – 4 = – 10 = 5

– 2 – 2

(x – S1) · (x – S2) = 0

(x – (– 1)) · (x – (1/6)) = 0

(x + 1) · (x – (1/3)) = 0

x² – (1/3)x + x – 1/3 = 0

x² + (2/3)x – 1/3 = 0

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