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Resposta:
Δ = 1² – 4.2.(– 3)
Δ = 1 + 24
Δ = 25
x = – 1 ± √25
2.2
x = – 1 ± 5
4
x' = – 1 + 5 = 4 = 1
4 4
x'' = – 1 – 5 = – 6 = – 3
4 4 2
As raízes da equação 2x² + x – 3 = 0 são 1 e – 3/2.
Δ = 6² – 4.(– 1).(– 5)
Δ = 36 – 20
Δ = 16
x = – 6 ± √16
2.(– 1)
x = – 6 ± 4
– 2
x' = – 6 + 4 = – 2 = 1
– 2 – 2
x'' = – 6 – 4 = – 10 = 5
– 2 – 2
(x – S1) · (x – S2) = 0
(x – (– 1)) · (x – (1/6)) = 0
(x + 1) · (x – (1/3)) = 0
x² – (1/3)x + x – 1/3 = 0
x² + (2/3)x – 1/3 = 0
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