Question

1) Resolva a adição de monômios: 10x² + 27x² *
1 ponto
37x²
27x²
20x²
12 x²
2) Resolva a subtração de monômios: 10x² - 12 x²
1 ponto
3x²
4x²
-2x²
-5x²
3) Resolva a multiplicação de monômios: 3x²y² . 4x²y²
1 ponto
11 x⁴y
12 x⁴y⁴
3 x⁴y⁴
4 x²y⁴
Ajudem plss
Fotinha da Park • 3•​

Answer 1

Calculando, iremos obter:

$\boxed{\mathtt{\boxed{\mathtt{1 = 37x {}^{2} }}}} \\ \: \boxed{\mathtt{\boxed{\mathtt{2 = - 2x {}^{2} }}}} \\ \: \: \: \: \boxed{\mathtt{\boxed{\mathtt{3 = 12x {}^{4} y {}^{4} }}}}$

❏ Vamos ao entendimento!

1-

$\mathtt{10x {}^{2} + 27x {}^{2} }$

• Coloque termos similares em evidência, e some seus coeficientes.

$\mathtt{(10 + 27)x {}^{2} }$

• Some os números.

$\mathtt{37x {}^{2} }$

$\boxed{\begin{array}{lr}\bf{{\purple{Conta \: armada...}}} \\ \\ \bf{{\blue{ \: \: \: \: 10x {}^{2} + 27x {}^{2} }}} \\ \bf{{\blue{ \: \: \: \: (10 + 27)x {}^{2} }}} \\ \bf{{\blue{ \: \: \: \: \: \: \: \: \: \: \: 37x {}^{2} }}}\end{array}}$

2-

$\mathtt{10x {}^{2} - 12x {}^{2} }$

• Coloque termos similares em evidência, e subtraia seus coeficientes.

$\mathtt{(10 - 12)x {}^{2} }$

• Matenha o sinal do número com o maior valor absoluto, e subtraia dele o menor valor absoluto.

$\mathtt{ - (12 - 10)}$

• Subtraia.

$\mathtt{ - 2x {}^{2} }$

$\boxed{\begin{array}{lr}\bf{{\purple{Conta \: armada...}}} \\ \\ \bf{{\blue{ \: \: \: \: 10x {}^{2} - 12x {}^{2} }}} \\ \bf{{\blue{ \: \: \: \: (10 - 12)x {}^{2} }}} \\\bf{{\blue{ \: \: \: \: \: \: \: \: \: - 2x {}^{2} }}} \end{array}}$

3-

$\mathtt{3x {}^{2} y {}^{2} \times 4x {}^{2} y {}^{2} }$

• Multiplique os números.

$\mathtt{12x {}^{2}y {}^{2} x {}^{2} y {}^{2} }$

• Multiplique os termos com a mesma base somando os seus expoentes.

$\mathtt{12x {}^{2 + 2}y {}^{2} \times y {}^{2} }$

• Multiplique os termos com a mesma base somando os seus expoentes.

$\mathtt{12x {}^{2 + 2}y {}^{2 + 2} }$

• Some...

$\mathtt{12x {}^{4}y {}^{2 + 2} }$

• Some novamente.

$\mathtt{12x {}^{4}y {}^{4} }$

$\boxed{\begin{array}{lr}\bf{{\purple{Conta \: armada...}}} \\ \\ \bf{{\blue{ \: \: \: 3x {}^{2}y {}^{2} \times 4x {}^{2} y {}^{2} }}} \\\bf{{\blue{ \: \: \: \: \: 12x {}^{2} y {}^{2}x {}^{2}y {}^{2} }}} \\\bf{{\blue{ \: \: 12x {}^{2 + 2}y {}^{2} \times y {}^{2} }}} \\\bf{{\blue{ \: \: \: \: 12x {}^{2 + 2} y {}^{2 + 2} }}} \\\bf{{\blue{ \: \: \: \: \: \: 12x {}^{4}y {}^{2 + 2} }}} \\ \bf{{\blue{ \: \: \: \: \: \: \: \: \: 12x {}^{4}y {}^{4} }}}\end{array}}$

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❏ brainly.com.br/tarefa/17880688

❏ brainly.com.br/tarefa/21823638

✽+†+✽――――――――――――――――

$\mathbf{{\purple{\boxed{\boxed{\mathbf{{\purple{\boxed{\mathbf{{\blue{Att: Bellinha}}}}}}}}}}}}$

Answer 2

Vamos lá!

$\boxed{\begin{array}{lr}\mathtt{{\red{1 = 10x {}^{2} + 27x {}^{2} }}} \\ \mathtt{{\red{ \: \: \: \: (10 + 27)x {}^{2} }}} \\ \mathtt{{\red{ \: \: \: \: \: \: \: \: \: \: 37x {}^{2} }}}\end{array}} \\ \boxed{\begin{array}{lr}\mathtt{{\red{2 = 10x {}^{2} - 12x {}^{2} }}} \\ \mathtt{{\red{ \: \: \: \: (10 - 12)x {}^{2} }}} \\\mathtt{{\red{ \: \: \: \: \: \: \: \: - 2x {}^{2} }}}\end{array}} \\ \boxed{\begin{array}{lr}\mathtt{{\red{ 3 = 3x {}^{2} y {}^{2} \times 4x {}^{2}y {}^{2} }}} \\ \mathtt{{\red{ \: \: \: \: \: \: 12x {}^{2}y {}^{2}x {}^{2} y {}^{2} }}} \\ \mathtt{{\red{ \: \: \: 12x {}^{2 + 2}y {}^{2} \times y {}^{2} }}} \\\mathtt{{\red{ \: \: \: \: \: 12x {}^{2 + 2} y {}^{2 + 2} }}} \\ \mathtt{{\red{ \: \: \: \: \: \: \: 12x {}^{4} y {}^{2 + 2} }}} \\ \mathtt{{\red{ \: \: \: \: \: \: \: \: \: 12x {}^{4}y {}^{4} }}}\end{array}}$