Question

[(-5/7)×√49/25+(-1/4)^4×√16]÷(-1/4+1)
(-1/4)^2-3/7×[1/6-(-1/2)^3]
(-2/3^2)+[(-1/2)^3÷(-2)-(1-1/2)^2]
(1+3/5)÷(√9-3/5)-(1-1/4)×(-1+1/3)
(1-1/2)^3+(1/2-1)^4-(-1/2-1)^2
​

Answer 1

Resposta:

Explicação passo a passo:

[(-5/7)×√49/25+(-1/4)^4×√16]÷(-1/4+1)

[(-5/7)×7/5 + 1/256×4]÷(3/4)

[-1 + 1/64]÷(3/4)

-63/64 : 3/4

-63/64 * 4/3

-21/16 ou -1,3125

(-1/4)^2-3/7×[1/6-(-1/2)^3]

1/16 - 3/7×[1/6-(-1/8)]

1/16 - 3/7×[1/6+1/8]

1/16 - 3/7×7/24]

1/16 - 1/8 =

-1/16

(-2/3^2)+[(-1/2)^3÷(-2)-(1-1/2)^2]

4/9 + [-1/8÷(-2)-(1/2)^2]

4/9 + [-1/8÷(-2)-1/4]

4/9 + [1/16-1/4]

4/9 - 3/16

37/144

(1+3/5)÷(√9-3/5)-(1-1/4)×(-1+1/3)

(8/5) ÷ (3 -3/5) - (3/4) × (-2/3)

(8/5) ÷ (12/5) - (3/4) × (-2/3)

8/5 * 5/12 - 3/4 * -2/3

40/60 + 6/12

2/3 + 1/2

7/6

(1-1/2)^3+(1/2-1)^4-(-1/2-1)^2

(1/2)^3 + (-1/2)^4 - (-3/2)^2

1/8 + 1/16 - 9/4

(mmc entre 4, 8 e 16 = 16)

(2+1-36)/16

-33/16