Question

Tesolva a equaçoes
X2+3x-4=0

Answer 1

x² + 3x - 4 = 0

Δ = b²−4ac
Δ = (3)²−4⋅1⋅−4
Δ = 9+16
Δ = 25

x = -b ± √Δ / 2.a

x = -3 ± √25 / 2.1
x = -3 ± 5 / 2
x' = -3 + 5 / 2
x' = 2/2
x' = 1

x'' = -3 - 5 / 2
x'' = -8/2
x'' = -4

S ={1,  -4}