Question

Fatore as expressões abaixo:

a) 27x³+8

b) 1000z³+1

c) x³-y³​

Answer 1

(a+b)³=a³+3a²b+3ab²+b³

(a+b)³=a³+b³+3ab*(a+b)

a³+b³=(a+b)³-3ab*(a+b)

a³+b³=(a+b)*[(a+b)²-3ab]

a³+b³=(a+b)*[a²+2ab+b²-3ab]

a³+b³=(a+b)*(a²+b²-ab)

a) 27x³+8 =(3x)³+2³

a=3x

b=2

27x³+8 = (3x+2)*(9x²+4-6x)

b)

1000z³+1=(10z)³+1

a=10z

b=1

1000z³+1=(10z+1)*(100z²+1-10z)

c)

x³-y³​=?

a= x

b= -y

x³-y³​=(x-y)*(x²+y²+xy)