Question

A derivada da função y= (x+1) (2x-1) é:
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Answer 1

Resposta:

Logo, a derivada é y'=2. Abraço! bons estudos!!!

Answer 2

$\frac{d}{dx}c=0\\\\\frac{d}{dx}x^n=nx^{n-1}\\\\\\\\\frac{d}{dx}(x+1)(2x-1)\\\\\frac{d}{dx}(2x^2+x-1)\\\\2.2x^{2-1}+x^{1-1}+0\\\\\frac{d}{dx}(f(x))=4x+1$