Question

qual o numero de mols de atomos de gás ozonio (O3) que ocupa um volume de 69,2 na CNTP

Answer 1

$\boxed{\begin{array}{l}\sf 3\cdot6\cdot10^{23}~mols~de~\acute atomos\longrightarrow 22,4~L\\\sf x\longrightarrow 69,2~L\\\sf 22,4x=1245,6\cdot10^{23}\\\sf x=\dfrac{1245,6\cdot10^{23}}{22,4}\\\sf x=55,6\cdot10^{23}~mols~de~\acute atomos\end{array}}$