Question

Me ajudem pf.. log de 0,008 na base 25

Answer 1

$log_{25}(0,008)=log_{25}( \frac{8}{1000} )=log_{25}( \frac{1}{125} )=log_{25}(1)-log_{25}(125)=$
$log_{25}(1)-log_{25}(5^3)$
$log_{25}(1)-log_{25}((25)^{\frac{3}{2}})$
0-3/2
-3/2