Question

cálcule as potencias

a)4-³=

b)(3/7)-⁴=

c)2-5=

d)-5/4)-³=​

Answer 1

Oie, tudo bom?

a)

$= 4 {}^{ - 3} \\ = \frac{1}{4 {}^{3} } \\ \boxed{ = \frac{1}{64} }$

b)

$= ( \frac{3}{7} ) {}^{ - 4} \\ = ( \frac{7}{3} ) {}^{4} \\ = \frac{7 {}^{4} }{3 {}^{4} } \\ \boxed{ = \frac{2401}{81} }$

c)

$= 2 {}^{ - 5} \\ = \frac{1}{2 {}^{5} } \\ \boxed{ = \frac{1}{32} }$

d)

$( - \frac{5}{4} ) {}^{ - 3} \\ = ( - \frac{4}{5} ) {}^{3} \\ = - ( \frac{4}{5} ) {}^{3} \\ = - \frac{4 {}^{3} }{5 {}^{3} } \\ \boxed{ = - \frac{64}{125} }$

Att. NLE Top Shotta

Answer 2

Resposta:

cálcule as potencias

a)4-³= 64

b)(3/7)-⁴= 343

c)2-5= 3⁴

d)-5/4)-³= -125/64