determine a temperatura A)43°C->°F B)60°C->°F C)400°F->°C D)25°C->K E)200K->°C F)98°F->K
yasmin342:
tc/5=tf-32/9. tc/5=98-32/9. tc/5=66/9. tc9=330. tc=330/9=36.6c. segunda parte. tc=tk-273. tk-273=36.6. tk=36.6+273. tk=309.6k
Respostas
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a)-tc/5=tf-32/9
43/5=tf-32/9
5tf-160=387
5TF=387+169
5TF=547
TF=547/5
TF=109.4
b)-tc/5=tf-32/9
60/5=tf-32/9
12=tf-32/9
tf-32=108
tf=108+32=140f
c)-tc/5=tf-32/9
tc/5=400-32/9
tc/5=368/9
tc9=1840
tc=1840/9=204.4c
d)-tc=tk-273
25=tk-273
tk-273=25
tk=25+273=298k
e)-tc=tk-273
tc=200-273
tc=-73c
43/5=tf-32/9
5tf-160=387
5TF=387+169
5TF=547
TF=547/5
TF=109.4
b)-tc/5=tf-32/9
60/5=tf-32/9
12=tf-32/9
tf-32=108
tf=108+32=140f
c)-tc/5=tf-32/9
tc/5=400-32/9
tc/5=368/9
tc9=1840
tc=1840/9=204.4c
d)-tc=tk-273
25=tk-273
tk-273=25
tk=25+273=298k
e)-tc=tk-273
tc=200-273
tc=-73c
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