Question

17. Determine a área do triângulo abaixo:​

Answer 1

$\Large\boxed{\begin{array}{l}\tt dados\begin{cases}\sf \theta=60^\circ\\\sf a=4~cm\\\sf b=5~cm\\\sf A=?\end{cases}\\\sf A=\dfrac{1}{2}\cdot a\cdot b\cdot sen(\theta)\\\\\sf A=\dfrac{1}{\backslash\!\!\!2}\cdot \backslash\!\!\!4^2\cdot5\cdot sen(60^\circ)\\\sf A=\backslash\!\!\!2\cdot5\cdot\dfrac{\sqrt{3}}{\backslash\!\!\!2}\\\sf A=5\sqrt{3}~cm^2\end{array}}$