Question

-x²+6x-5=0
encontre o valor de delta,pfvvvv​

Answer 1

Resposta:

∆= b² - 4ac

∆= 6² - 4(-1)(-5)

∆= 36 - 20

∆= 16

Answer 2

-x²+6x-5=0

A= -1, B=6, C=-5

Δ = b² - 4.a.c

Δ = 36 - 4 . -1 . -5

Δ = 36 - 20

Δ = 16