Question

me ajudem por favor!!!!
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Answer 1

Resposta:

$9x^2+\frac{3xy}{2}+\frac{y^2}{16}$

Explicação passo a passo:

$\left(3x+\frac{y}{4}\right)^2$

$=\left(\frac{12x+y}{4}\right)^2$

$=\frac{\left(12x+y\right)^2}{4^2}$

$=\frac{\left(12x+y\right)^2}{16}$

$=\frac{144x^2+24xy+y^2}{16}$

$=\frac{144x^2}{16}+\frac{24xy}{16}+\frac{y^2}{16}$

$=9x^2+\frac{24xy}{16}+\frac{y^2}{16}$

$=9x^2+\frac{3xy}{2}+\frac{y^2}{16}$