Question

(√b² - 4a) : (ab - 16), quando a = 3 e b = 7 *

Answer 1

Resposta:

(√b² - 4a) : (ab - 16)

$( \sqrt{ {7}^{2} } - 4 \times 3) \div (3 \times 7 - 16) \\ ( \sqrt{49} - 12) \div (21 - 16) \\ (7 - 12) \div 5 \\ \\ - 5 \div 5 \\ \\ - \frac{5}{5} \\ \\ = - 1$