Question

a) a2 - 16a + 64 = b) 100 + 20b + b2 =​

Answer 1

A) a² - 16a + 64

∆ = b² - 4 a c

∆ = -16² - 4 1 64

∆ = 256 - 256

∆ = 0

x = - b ± √∆ / 2.a

x = -16 ± 0 / 2.1

x = -16 ± / 2

x = -8

b) b² + 20b + 100

∆ = b² - 4 a c

∆ = 20² - 4 1 100

∆ = 400 - 400

∆ = 0

x = - b ± √∆ / 2.a

x = 20 ± 0 / 2.1

x = 20 ± / 2

x = 10