Question

Determine a fração geratriz das dízimas abaixo. a) 0,888... B) 0,848484.... C)4,272727.... D) 1,24888... E) 0,555... F) 0,424242... G) 0,111... H) 2,3888...

Answer 1

a)0,8888 = 8/9
b)0,8484848484....... = 84/99
c)4,2727272727....... = 4 + 27/99 = 4 x 99 + 27 /99 = 396 + 27 /99 =423/99 simplifica 141/33  =47/11
d)1,24888.... = 1 + 248 - 24 /900 = 1 + 224/900 = 1 x 900 + 224/900 = 
900 + 224 /900 = 1124/900  simplifica =281/225
e)0,555....=5/9
f)0,424242..... = 42/99  =14/33
g)0,111... = 1/9
h)2,3888.... = 2 + 38 - 3 /90 = 2 +  35 /90 = 2 x 90 + 35 /90 =
180 + 35 /90 = 215/90 =