• Matéria: Matemática
  • Autor: rosanepatricia5
  • Perguntado 3 anos atrás

1 - Dados os números 910−6

, 310−6

, 510−6 e 710−6 qual deles é o maior ?

a) ( ) 910−6

b) ( ) 310−6

c) ( ) 510−6

d) ( ) 710−6​

Respostas

respondido por: avdantas54321
1

Resposta:

Dados os números

9.10^-6

9.10-6

= 9/106

qual deles é o maior ?

a) (X) 9.10^-6 RESPOSTA

b) () 3.10^-6

c) () 5.10^-6

d) () 7.10^-6

Expicação passo a passo :

=9/10x10x10x10x10x10=9/1.000.0000 =

=9/10x10x10x10x10x10=9/1.000.0000 =3.10^-6 = 3/106 = 3/10x10x10x10x10x10= 3/1.000.000 = 0,000003

=9/10x10x10x10x10x10=9/1.000.0000 =3.10^-6 = 3/106 = 3/10x10x10x10x10x10= 3/1.000.000 = 0,0000035.10^-6 = 5/106 = 5/10x10x10x10x10x10= 5/1.000.000 = 0,000005

=9/10x10x10x10x10x10=9/1.000.0000 =3.10^-6 = 3/106 = 3/10x10x10x10x10x10= 3/1.000.000 = 0,0000035.10^-6 = 5/106 = 5/10x10x10x10x10x10= 5/1.000.000 = 0,0000057.10-6 = 7/106 = 7/10x10x10x10x10x10=

=9/10x10x10x10x10x10=9/1.000.0000 =3.10^-6 = 3/106 = 3/10x10x10x10x10x10= 3/1.000.000 = 0,0000035.10^-6 = 5/106 = 5/10x10x10x10x10x10= 5/1.000.000 = 0,0000057.10-6 = 7/106 = 7/10x10x10x10x10x10=7/1.000.000

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