Question

alguém me ajuda for favor,as questões 1 e 2 preciso disso hoje!!
(OBS: É PRECISO TER AS CONTAS)​

Answer 1

Resposta:

1)

a) 2$\sqrt{5}$

b) -2$\sqrt[3]{6}$

c) 2$\sqrt{3}$ + 3

d) -2$\sqrt[3]{2}$

2) 10$\sqrt{3}$ +2$\sqrt{2}$

Explicação passo a passo:

1.

a) $\sqrt{5}$ + 4

Basta somar as raízes

5$\sqrt{5}$ - 3

2$\sqrt{5}$

b) $\sqrt[3]{6}$ + 2

3$\sqrt[3]{6}$ - 5

c) $\sqrt{27}$ - $\sqrt{3}$ + 3 =

$\sqrt{9 * 3}$ - $\sqrt{3}$ + 3 =

$\sqrt{9} * \sqrt{3}$ - $\sqrt{3}$ + 3

3$\sqrt{3}$ -

2$\sqrt{3}$ + 3

d) $\sqrt[3]{16}$ + $\sqrt[3]{2}$ - 5

$\sqrt[3]{2*8}$ -4$\sqrt[3]{2}$ =

$\sqrt[3]{8}$ * $\sqrt[3]{2}$ - 4

2$\sqrt[3]{2}$ -4

-2$\sqrt[3]{2}$

2) Perímetro do retângulo é a soma dos 4 lados.

$\sqrt{3}$ - $\sqrt{2}$ + $\sqrt{8}$ + 4 =

10$\sqrt{3}$ -2$\sqrt{2}$ +2$\sqrt{8}$ =

10$\sqrt{3}$ -2$\sqrt{2}$ +2$\sqrt[2]{2*4}$ =

10$\sqrt{3}$ -2$\sqrt{2}$ +2($\sqrt{2}$*$\sqrt{4}$ )=

10$\sqrt{3}$ -2$\sqrt{2}$ +2(2$\sqrt{2}$) =

10$\sqrt{3}$ -2$\sqrt{2}$ +4$\sqrt{2}$ = 10$\sqrt{3}$ +2$\sqrt{2}$

Answer 2

Resposta:

$a)~~\\ \sqrt{5} +4\sqrt{5} -3\sqrt{5} =\\ \\ (1+4-3)\sqrt{5} =\\ \\\fbox{ 2\sqrt{5} }$

$b)\\ ~~\sqrt[3]{6} +2\sqrt[3]{6} -5\sqrt[3]{6} =\\ \\ (1+2-5)\sqrt[3]{6} =\\ \\\fbox{ -2\sqrt[3]{6} }$

$c)\\ ~~ \sqrt{27} -\sqrt{3} +3=\\ \\ \sqrt{3.3^2} -\sqrt{3} +3=\\ \\ 3\sqrt{3} -\sqrt{3} +3=\\ \\ \fbox{ 2\sqrt{3} +3 }$

$d)\\ ~~\sqrt[3]{16} +\sqrt[2]{2} -5\sqrt[3]{2} =\\ \\ \sqrt[3]{2.2^3} +\sqrt[3]{2} -5\sqrt[3]{2} =\\ \\ 2\sqrt[3]{2} +\sqrt[3]{2} -5\sqrt[3]{2} =\\ \\ (2+1-5)\sqrt[3]{2} =\\ \\ \fbox{ -2\sqrt[3]{2} }$

=============================

2)

Perímetro é a soma de todos os lados.

Temos 2 bases e 2 alturas iguais

$P=2.(\sqrt{3} -\sqrt{2} )+2.(\sqrt{8} +4\sqrt{3)} \\ \\ P=2\sqrt{3} -2\sqrt{2} +2\sqrt{8} +8\sqrt{3} \\ \\ P=10\sqrt{3} -2\sqrt{2} +2\sqrt{2.2^2} \\ \\ P=10\sqrt{3} -2\sqrt{2} +2.2\sqrt{2} \\ \\ P=10\sqrt{3} -2\sqrt{2} +4\sqrt{2} \\ \\\fbox{ Per\'imetro=10\sqrt{3} +2\sqrt{2} }$