Question

2x2 - 8x + 8 = 0 (r 2 )

Answer 1

Resposta:

2x² - 8x + 8

Δ = (-8)² - 4 (2)(8)

Δ = 64 - 64 = 0

x = -(-8) +- √Δ

2(2)

x = 8 +- 0

4

x¹ = 8 + 0 = 8 = 2

4 4

x² = 8 + 0 = 8 = 2

4 4

Resposta : 2