Question

alguem me ajuda aqui por favor

Answer 1

Explicação passo-a-passo:

A)

$\frac{x}{4} + 20 = \frac{x}{3} \\ \frac{3x + 240 = 4x}{12} \\ \\ - x = - 240 \: \: \: ( - 1) \\ x = 240$

B)

$\frac{2y}{5} - \frac{3}{4} = \frac{3y}{20} \\ \\ \frac{8y - 15 = 3y}{20} \\ \\ 5y = 15 \\ y = \frac{15}{5} = 3$

C)

$1 - \frac{x}{2} = - \frac{x}{3} + 2 \\ \\ \frac{6 - 3x = - 2x + 12 }{6} \\ \\ - x = 6 \\ x = - 6$

D)

$\frac{x - 10}{9} + \frac{x}{6} = 10 \\ \\ \frac{2(x - 10) + 3x = 180}{18} \\ \\ 2x - 20 + 3x = 180 \\ 5x = 200 \\ x = \frac{200}{5} = 40$

E)

$\frac{x + 3}{4} - \frac{x - 1}{3} = \frac{7}{2} \\ \\ \frac{3(x + 3) - 4(x -1) = 42}{12} \\ \\ 3x + 9 - 4x + 4 = 42 \\ - x + 13 = 42 \\ - x = 29 \\ x = - 29$

F)

$\frac{4x - 1}{10} - 2 = \frac{4}{3} - \frac{2 - x}{4} \\ \\ \frac{6(4x - 1) - 120 = 80 - 15(2 - x)}{60} \\ \\ 24x - 6 - 120 = 80 - 30 + 15x \\ 9x = 120 + 6 + 80 - 30 \\ 9x = 176 \\ x = \frac{176}{9}$