Question

resolva as equações: ​

Answer 1

$\\A)-\frac{x}{4} +3=\frac{x}{2} \\\\MMC\\\\\frac{-x+12}{4}=\frac{x}{2} (MULTIPLICA...CRUZADO) \\\\-2x+24=4x (DIVIDE...OS...DOIS...LADOS...POR...2)\\\\-x+12=2x\\\\3x=12\\\\x=\frac{12}{3} \\x=4\\\\B)26-\frac{5x}{6} =\frac{x}{6} +20\\\\\frac{156-5x}{6} =\frac{x+120}{6} (MULTIPLICA....CRUZADO)\\\\936-30x=6x+720\\-30x-6x=720-936\\-36x=-216\\36x=216\\x=\frac{216}{36} \\x=6$

Answer 2

Resposta:

Solução:

a)

$\displaystyle \sf -\;\dfrac{x}{4} + 3 = \dfrac{x}{2}$

$\displaystyle \sf 3 = \dfrac{x}{4} +\dfrac{x}{2}$

$\displaystyle \sf 3 = \dfrac{x}{4} + \dfrac{2x}{4}$

$\displaystyle \sf \dfrac{\diagup\!\!\!{ 3}\:^1}{1} = \dfrac{\diagup\!\!\!{ 3\:^1}x}{4}$

$\displaystyle \sf \dfrac{1}{1} = \dfrac{x}{4}$

$\boxed{ \boxed { \boldsymbol{ \displaystyle \sf x = 4 }}} \quad \gets \text{\sf \textbf{Resposta } }$

Portanto:  S = {4}.

b)

$\displaystyle \sf 26 -\: \dfrac{5x}{6} = \dfrac{x}{6} + 20$

$\displaystyle \sf 26 - 20 = \dfrac{5x}{6} + \dfrac{x}{6}$

$\displaystyle \sf 6 = \dfrac{\diagup\!\!\!{ 6} x}{ \diagup\!\!\!{ 6} }$

$\displaystyle \sf 6 = x$

$\boxed{ \boxed { \boldsymbol{ \displaystyle \sf x = 6 }}} \quad \gets \text{\sf \textbf{Resposta } }$

Portanto:  S = {6}.

''Ser imparcial não significa não ter princípio, e sim profissional''.

                Willyan Taglialenha.

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